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uk.sci.weather (UK Weather) (uk.sci.weather) For the discussion of daily weather events, chiefly affecting the UK and adjacent parts of Europe, both past and predicted. The discussion is open to all, but contributions on a practical scientific level are encouraged. |
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#11
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In article ,
Len Wood writes: What chance of winter mean temp going below zero C in Wanstead? ----------------------------------------------------------------- Zero if you ask me. snip Well it very nearly happened in 1962-3, so though very unlikely it's not impossible. -- John Hall "He crams with cans of poisoned meat The subjects of the King, And when they die by thousands G.K.Chesterton: Why, he laughs like anything." from "Song Against Grocers" |
#12
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On Tuesday, December 17, 2013 7:23:56 PM UTC, John Hall wrote:
In article , Scott W writes: Further to Dave Cornwell's comment a few weeks back that people mostly remember a winter through the amount of days with snow lying I decided to use the data I produced for my winter forecast and try to find out what snow cover has been like in my area going back to 1946/47 - the first year of the original snow survey. I then divided the snow lying days by the winter mean to give the index. I realise there is the work of Bonacina to consider but as this is national I wanted to look more indepth That's very interesting. Thanks for going to the trouble of producing it. If snow cover is the main interest, then why divide the number of days with lying snow by the mean temperature? Because the mean for 1962-3 was 0.2C and that for 1946-7 was 1.3C, the division massively inflates the index for 1962-3 compared to the earlier winter. (And what would you have done if the mean for 1962-3 had come out negative, as it very nearly did? ![]() Hello John, I have modified the spreadsheet and used Kelvin instead of mean temp. I have divided snow lying by average mean Kelvin then multiplied by 100 to give it a chunky figure. The temperature stats refer to the meteorological winter - December, January, February. The snowfall stats refer to October to May. I realise this is not consistent but I was merely trying to give a 'perception' of each winter. One could argue that I should include temp stats and rainfall to go with the snowfall data ie October to May - but then this would introduce its own inconsistencies in not being 'meteorological winter'. With a couple of exceptions all my snowfall occurs December to March. Further feedback welcomed. Here is a link to the new spreadsheet http://sdrv.ms/1hZwtkG |
#13
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With a couple of exceptions all my snowfall occurs December to March. Further feedback welcomed.
Sorry, make that December to February -- ------------------------------ This email was sent by a company owned by Pearson plc, registered office at 80 Strand, London WC2R 0RL. Registered in England and Wales with company number 53723. |
#14
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In article ,
Scott W writes: I have modified the spreadsheet and used Kelvin instead of mean temp. I have divided snow lying by average mean Kelvin then multiplied by 100 to give it a chunky figure. The temperature stats refer to the meteorological winter - December, January, February. The snowfall stats refer to October to May. I realise this is not consistent but I was merely trying to give a 'perception' of each winter. One could argue that I should include temp stats and rainfall to go with the snowfall data ie October to May - but then this would introduce its own inconsistencies in not being 'meteorological winter'. With a couple of exceptions all my snowfall occurs December to March. Further feedback welcomed. The trouble with dividing by degrees Kelvin is that there will then be very little difference between cold winters and mild ones. Dividing by 274 (1C) in one case and 278 (5c) in the other won't affect the result that much. So whereas dividing by the Celsius temperature meant that temperature tended to dominate over snowfall, dividing by the Kelvin value will result in the reverse. If you want both snowfall and temperature to have roughly equal weight, then I think you need to experiment until you get something that "feels" right. I'm not sure that dividing one value by the other is the way to go. If you find that the median number of days with snow lying is 10, say, and the median (or mean - it won't make much difference here) Celsius temperature over all winters is 4, say, then how about an index L-(10/4)*T, where L is the number of days with snow lying and T the mean Celsius temperature of the winter in question? That looks as if it might give reasonable weightings to the two factors, and will mean that the median winter will have an index of zero. (I think that for days of snow lying the median value is more "typical" than the mean, as the mean is bumped up by the occasional very snowy winter like 1962-3.) On second thoughts my suggestion would probably still over-emphasise snowfall in relation to temperature, as the number of days of snow lying can be anywhere between zero and 60-70, whereas the limits on winter mean temperature are probably between about zero and 6-7. So the range of values of the former is about ten times that of the latter. To compensate for that, a possible index might be L - 10*T. So a very mild and non-snowy winter would have a value of about -60 or -70, and a very cold and snowy one like 1962-3 would have a value of +60 or +70. An average winter would be about 10 - 10*4 = -30. If you'd rather the average index was close to zero you could use 30 + L - 10*T. -- John Hall "He crams with cans of poisoned meat The subjects of the King, And when they die by thousands G.K.Chesterton: Why, he laughs like anything." from "Song Against Grocers" |
#15
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John Hall wrote:
In article , Scott W writes: I have modified the spreadsheet and used Kelvin instead of mean temp. I have divided snow lying by average mean Kelvin then multiplied by 100 to give it a chunky figure. The temperature stats refer to the meteorological winter - December, January, February. The snowfall stats refer to October to May. I realise this is not consistent but I was merely trying to give a 'perception' of each winter. One could argue that I should include temp stats and rainfall to go with the snowfall data ie October to May - but then this would introduce its own inconsistencies in not being 'meteorological winter'. With a couple of exceptions all my snowfall occurs December to March. Further feedback welcomed. The trouble with dividing by degrees Kelvin is that there will then be very little difference between cold winters and mild ones. Dividing by 274 (1C) in one case and 278 (5c) in the other won't affect the result that much. So whereas dividing by the Celsius temperature meant that temperature tended to dominate over snowfall, dividing by the Kelvin value will result in the reverse. If you want both snowfall and temperature to have roughly equal weight, then I think you need to experiment until you get something that "feels" right. I'm not sure that dividing one value by the other is the way to go. If you find that the median number of days with snow lying is 10, say, and the median (or mean - it won't make much difference here) Celsius temperature over all winters is 4, say, then how about an index L-(10/4)*T, where L is the number of days with snow lying and T the mean Celsius temperature of the winter in question? That looks as if it might give reasonable weightings to the two factors, and will mean that the median winter will have an index of zero. (I think that for days of snow lying the median value is more "typical" than the mean, as the mean is bumped up by the occasional very snowy winter like 1962-3.) On second thoughts my suggestion would probably still over-emphasise snowfall in relation to temperature, as the number of days of snow lying can be anywhere between zero and 60-70, whereas the limits on winter mean temperature are probably between about zero and 6-7. So the range of values of the former is about ten times that of the latter. To compensate for that, a possible index might be L - 10*T. So a very mild and non-snowy winter would have a value of about -60 or -70, and a very cold and snowy one like 1962-3 would have a value of +60 or +70. An average winter would be about 10 - 10*4 = -30. If you'd rather the average index was close to zero you could use 30 + L - 10*T. Sorry John, I can't agree with that. Using the temperature expressed in deg C in this way is akin to saying that a day with a max of 4 deg C is twice as warm as a day with a max of 2 deg C which, I think you would agree, is nonsense. Using deg K is the only valid method. The new spreadsheet that Scott has devised does appear to show a realistic spread in the relative severity of individual winters. -- Norman Lynagh Tideswell, Derbyshire 303m a.s.l. |
#16
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"Norman" wrote in message ...
John Hall wrote: On second thoughts my suggestion would probably still over-emphasise snowfall in relation to temperature, as the number of days of snow lying can be anywhere between zero and 60-70, whereas the limits on winter mean temperature are probably between about zero and 6-7. So the range of values of the former is about ten times that of the latter. To compensate for that, a possible index might be L - 10*T. So a very mild and non-snowy winter would have a value of about -60 or -70, and a very cold and snowy one like 1962-3 would have a value of +60 or +70. An average winter would be about 10 - 10*4 = -30. If you'd rather the average index was close to zero you could use 30 + L - 10*T. Sorry John, I can't agree with that. Using the temperature expressed in deg C in this way is akin to saying that a day with a max of 4 deg C is twice as warm as a day with a max of 2 deg C which, I think you would agree, is nonsense. Using deg K is the only valid method. I don't agree, Norman. I think John's method is perfectly valid, as the 'index' (like a temperature scale) has an arbitrary zero point which can be chosen at will and only differences in its value (not ratios) are meaningful. A max of 4C compared to a max of 2C will just subtract '2 degrees worth' of severity from the index, ie 20 points on his scale. And this will work exactly the same whether you use deg K or deg C - it just changes the zero point of the index. Subtracting (some multiple of) the temperature is much better than dividing, since it makes the index linear in both L and T. |
#17
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Gavino wrote:
"Norman" wrote in message ... John Hall wrote: On second thoughts my suggestion would probably still over-emphasise snowfall in relation to temperature, as the number of days of snow lying can be anywhere between zero and 60-70, whereas the limits on winter mean temperature are probably between about zero and 6-7. So the range of values of the former is about ten times that of the latter. To compensate for that, a possible index might be L - 10*T. So a very mild and non-snowy winter would have a value of about -60 or -70, and a very cold and snowy one like 1962-3 would have a value of +60 or +70. An average winter would be about 10 - 10*4 = -30. If you'd rather the average index was close to zero you could use 30 + L - 10*T. Sorry John, I can't agree with that. Using the temperature expressed in deg C in this way is akin to saying that a day with a max of 4 deg C is twice as warm as a day with a max of 2 deg C which, I think you would agree, is nonsense. Using deg K is the only valid method. I don't agree, Norman. I think John's method is perfectly valid, as the 'index' (like a temperature scale) has an arbitrary zero point which can be chosen at will and only differences in its value (not ratios) are meaningful. A max of 4C compared to a max of 2C will just subtract '2 degrees worth' of severity from the index, ie 20 points on his scale. And this will work exactly the same whether you use deg K or deg C - it just changes the zero point of the index. Subtracting (some multiple of) the temperature is much better than dividing, since it makes the index linear in both L and T. -------------------------------------------------------------------- I can't tell you how pleased I am to see people once again thinking about the weather in an intersting way and coming up with some varied and interesting ideas on UKSW. Having tried some similar things I realise how difficult it is. I agree with Scott that there is more to a severe winter than the superficial perceptions people have and also how difficult it is to represent those perceptions mathematically. Dave |
#18
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Gavino wrote:
"Norman" wrote in message ... John Hall wrote: On second thoughts my suggestion would probably still over-emphasise snowfall in relation to temperature, as the number of days of snow lying can be anywhere between zero and 60-70, whereas the limits on winter mean temperature are probably between about zero and 6-7. So the range of values of the former is about ten times that of the latter. To compensate for that, a possible index might be L - 10*T. So a very mild and non-snowy winter would have a value of about -60 or -70, and a very cold and snowy one like 1962-3 would have a value of +60 or +70. An average winter would be about 10 - 10*4 = -30. If you'd rather the average index was close to zero you could use 30 + L - 10*T. Sorry John, I can't agree with that. Using the temperature expressed in deg C in this way is akin to saying that a day with a max of 4 deg C is twice as warm as a day with a max of 2 deg C which, I think you would agree, is nonsense. Using deg K is the only valid method. I don't agree, Norman. I think John's method is perfectly valid, as the 'index' (like a temperature scale) has an arbitrary zero point which can be chosen at will and only differences in its value (not ratios) are meaningful. A max of 4C compared to a max of 2C will just subtract '2 degrees worth' of severity from the index, ie 20 points on his scale. And this will work exactly the same whether you use deg K or deg C - it just changes the zero point of the index. Subtracting (some multiple of) the temperature is much better than dividing, since it makes the index linear in both L and T. You're right, Gavino. I obviously didn't read John's post correctly. I thought he was still suggesting dividing by the temperature but he is not. I agree that in John's proposed method it doesn't matter whether deg C or deg K are used - apologies John :-) -- Norman Lynagh Tideswell, Derbyshire 303m a.s.l. |
#19
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Hi
I too applaud Scott's attempt to produce a Winter Index. But does anyone have the article in the Weather magazine (maybe from the 1970's) on the same topic of "Winter Index"? I'm sure that it followed a similar article on a "Summer Index". As a Summer Index would require temperature, precipitation and sunshine, then a winter index can only work if you include both precipitation (ideally snowfall) and temperature anomalies. I tried to do this earlier this year in a blog I called "Central England Snowfall" in which I attempted to link CET and EWR. What it showed was: If you like snow 1946/47 is the winter to beat (although 1978/79 came close especially in the north), and if you like cold 1962/63 was intensely cold and rather dry. Bruce. PS Here's a link to my "Central England Snowfall" blog. http://xmetman.wordpress.com/2013/08...land-snowfall/ |
#20
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In article ,
Norman writes: John Hall wrote: On second thoughts my suggestion would probably still over-emphasise snowfall in relation to temperature, as the number of days of snow lying can be anywhere between zero and 60-70, whereas the limits on winter mean temperature are probably between about zero and 6-7. So the range of values of the former is about ten times that of the latter. To compensate for that, a possible index might be L - 10*T. So a very mild and non-snowy winter would have a value of about -60 or -70, and a very cold and snowy one like 1962-3 would have a value of +60 or +70. An average winter would be about 10 - 10*4 = -30. If you'd rather the average index was close to zero you could use 30 + L - 10*T. Sorry John, I can't agree with that. Using the temperature expressed in deg C in this way is akin to saying that a day with a max of 4 deg C is twice as warm as a day with a max of 2 deg C which, I think you would agree, is nonsense. I agree if you consider the temperature in isolation. And the effect if you divide one value by the other would clearly be totally wrong. But I don't think it's a problem with the formula above, because the constant of 10 has been chosen to be compatible with the possible range of values and because the lower end of the range of possible values happens, very conveniently, to be zero. When I have time I'll use Scott's values of L and T with my formula to see what the table would become and if it looks reasonable. I now see that Gavino has said that much more clearly than I've managed. My thanks to him. Using deg K is the only valid method. The new spreadsheet that Scott has devised does appear to show a realistic spread in the relative severity of individual winters. I haven't seen the results using K temperatures yet, but it seems to me that they would lead to the importance of temperature to be underestimated compared to the number of days with snow lying. If there's a problem it will only show up for the occasional winters that are mild overall but still have a large number of days of snow and those that are cold but non-snowy. -- John Hall "He crams with cans of poisoned meat The subjects of the King, And when they die by thousands G.K.Chesterton: Why, he laughs like anything." from "Song Against Grocers" |
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