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uk.sci.weather (UK Weather) (uk.sci.weather) For the discussion of daily weather events, chiefly affecting the UK and adjacent parts of Europe, both past and predicted. The discussion is open to all, but contributions on a practical scientific level are encouraged. |
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#171
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![]() "RedAcer" wrote in message ... On 10/08/15 16:53, RedAcer wrote: On 10/08/15 15:12, Alastair McDonald wrote: "RedAcer" wrote in message The hotter body will cool anyway whether the colder body is there or not. The radiation from the colder body means that the hot body will cool more slowly that it would have done if the cold body weren't there. It is not 'cold' radiation as you keep insisting. It does not cool the hot body, it warms it up.(I'm assuming no background bodies or source of radiation) There is always background radiation of one type or another. Think about it. You are either surrounded by walls, or by the earth and sky, or by cosmic background radiation. Describe a real situation where it does not exist. We are all trying to explain some physics to you. The way that it's done (in any physics class/book) is to concentrate on the salient features of interest in the system and ignore/minimise other 'smaller' effects. Assume we doing the experiment out in space where the CMBR is at 2.3K. Let the cold body be at 200K and the hot at 300K. OK. Terms of in the SB equation are proportional to T^4 and so can easily be ignored in a first approximation. Last sentence not very clear, should be:- "Terms in the SB equation are proportional to T^4 an so the CMBR can ignored in a first approximation." You are making the same mistake as Alan LeHun in the Four Question thread. You have not got a two body system. It is a three bodies when you include the CMBR. In that case the main source of cold radiation is the coldest body - the CMBR. It is not the cooler of the two bodies. If you then approximate the CMBR, which is the source of the cold radiation, to zero, then of course the cold radiation does not exist. But that is because you have approximated it to zero. You can't just approximate numbers to zero, particulary if they are divisors, which of course they aren't in this case. I think you have a bit more to learn before you try to teaching me. Cheers, Alastair. |
#172
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On Monday, August 10, 2015 at 6:07:01 PM UTC+1, Alastair wrote:
"RedAcer" wrote in message ... On 10/08/15 16:53, RedAcer wrote: On 10/08/15 15:12, Alastair McDonald wrote: "RedAcer" wrote in message The hotter body will cool anyway whether the colder body is there or not. The radiation from the colder body means that the hot body will cool more slowly that it would have done if the cold body weren't there. It is not 'cold' radiation as you keep insisting. It does not cool the hot body, it warms it up.(I'm assuming no background bodies or source of radiation) There is always background radiation of one type or another. Think about it. You are either surrounded by walls, or by the earth and sky, or by cosmic background radiation. Describe a real situation where it does not exist. We are all trying to explain some physics to you. The way that it's done (in any physics class/book) is to concentrate on the salient features of interest in the system and ignore/minimise other 'smaller' effects. Assume we doing the experiment out in space where the CMBR is at 2.3K. Let the cold body be at 200K and the hot at 300K. OK. Terms of in the SB equation are proportional to T^4 and so can easily be ignored in a first approximation. Last sentence not very clear, should be:- "Terms in the SB equation are proportional to T^4 an so the CMBR can ignored in a first approximation." You are making the same mistake as Alan LeHun in the Four Question thread. You have not got a two body system. It is a three bodies when you include the CMBR. In that case the main source of cold radiation is the coldest body - the CMBR. It is not the cooler of the two bodies. If you then approximate the CMBR, which is the source of the cold radiation, to zero, then of course the cold radiation does not exist. But that is because you have approximated it to zero. You can't just approximate numbers to zero, particulary if they are divisors, which of course they aren't in this case. I think you have a bit more to learn before you try to teaching me. Cheers, Alastair. Everyone is making the same 'mistake' as each other - not believing you about 'cold radiation', as its existence would mean re-writing the laws of thermodynamics. Don't you think that is slightly odd? No-one in science would back you, yet you think you are completely right. That makes you a genius, well worthy of the Nobel prize, or a completely deluded idiot, wouldn't you agree, Alastair? |
#173
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"Alastair McDonald" wrote in message ...
snip Alastair, may I ask you one question? Are you actually serious about this or just playing your own little private game at everyone else's expense? It's surely got to be some sort of game? |
#174
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On 10/08/15 18:06, Alastair McDonald wrote:
"RedAcer" wrote in message ... On 10/08/15 16:53, RedAcer wrote: On 10/08/15 15:12, Alastair McDonald wrote: "RedAcer" wrote in message The hotter body will cool anyway whether the colder body is there or not. The radiation from the colder body means that the hot body will cool more slowly that it would have done if the cold body weren't there. It is not 'cold' radiation as you keep insisting. It does not cool the hot body, it warms it up.(I'm assuming no background bodies or source of radiation) There is always background radiation of one type or another. Think about it. You are either surrounded by walls, or by the earth and sky, or by cosmic background radiation. Describe a real situation where it does not exist. We are all trying to explain some physics to you. The way that it's done (in any physics class/book) is to concentrate on the salient features of interest in the system and ignore/minimise other 'smaller' effects. Assume we doing the experiment out in space where the CMBR is at 2.3K. Let the cold body be at 200K and the hot at 300K. OK. Terms of in the SB equation are proportional to T^4 and so can easily be ignored in a first approximation. Last sentence not very clear, should be:- "Terms in the SB equation are proportional to T^4 an so the CMBR can ignored in a first approximation." You are making the same mistake as Alan LeHun in the Four Question thread. You have not got a two body system. It is a three bodies when you include the CMBR. In that case the main source of cold radiation is the coldest body - the CMBR. It is not the cooler of the two bodies. If you then approximate the CMBR, which is the source of the cold radiation, to zero, then of course the cold radiation does not exist. But that is because you have approximated it to zero. You can't just approximate numbers to zero, particulary if they are divisors, which of course they aren't in this case. I think you have a bit more to learn before you try to teaching me. Cheers, Alastair. Clearly you do not understand physics. Write the SB equations for this system and show how big the CMBR is compared to to the bodies at 200 and 300 K. Do the calculations with and without it. hint 2^4 = 16 200^4 = 1,600,000,000 Before you start read this. https://en.wikipedia.org/wiki/Dunning%E2%80%93Kruger_effect You are on your own now. |
#175
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On 10/08/15 18:21, JohnD wrote:
"Alastair McDonald" wrote in message ... snip Alastair, may I ask you one question? Are you actually serious about this or just playing your own little private game at everyone else's expense? It's surely got to be some sort of game? I wondered that, but I think it's more likely to be a case of Dunning-Kruger. |
#176
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On Mon, 10 Aug 2015 18:21:24 +0100, "JohnD" wrote:
"Alastair McDonald" wrote in message ... snip Alastair, may I ask you one question? Are you actually serious about this or just playing your own little private game at everyone else's expense? It's surely got to be some sort of game? I had theoriginal Alastair McDonald on the "sensible" list. the other one, going by just Alastair as "non-sensible" and I'd assumed they were two different people. Maybe not. -- Regards, Paul Herber http://www.paulherber.co.uk/ |
#177
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On 10/08/15 18:58, Paul Herber wrote:
On Mon, 10 Aug 2015 18:21:24 +0100, "JohnD" wrote: "Alastair McDonald" wrote in message ... snip Alastair, may I ask you one question? Are you actually serious about this or just playing your own little private game at everyone else's expense? It's surely got to be some sort of game? I had theoriginal Alastair McDonald on the "sensible" list. the other one, going by just Alastair as "non-sensible" and I'd assumed they were two different people. Maybe not. Hmmm. I'd been assuming they were the same person - I'm not sure now ![]() |
#178
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On Monday, August 10, 2015 at 6:21:52 PM UTC+1, JohnD wrote:
"Alastair McDonald" wrote in message ... snip Alastair, may I ask you one question? Are you actually serious about this or just playing your own little private game at everyone else's expense? It's surely got to be some sort of game? He's always believed in this silly 'cold radiation'. There was a similar response to him trying to propose this a few years ago, but he didn't learn. Even when he eventually slips away from this thread he will **still** believe there is such a thing as 'cold radiation; that cool bodies can somehow cool warmer ones by some weird cryogenic rays. I'm still waiting for him to re-write physics, but that's just not happening, which is a shame, really. |
#179
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![]() "RedAcer" wrote in message ... On 10/08/15 18:21, JohnD wrote: "Alastair McDonald" wrote in message ... snip Alastair, may I ask you one question? Are you actually serious about this or just playing your own little private game at everyone else's expense? It's surely got to be some sort of game? I wondered that, but I think it's more likely to be a case of Dunning-Kruger. Well I guess you know all about that :-) |
#180
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![]() "Martin Brown" wrote in message ... He isn't interested in the truth, only in making me appear foolish. You have excelled in quest that by your original post and inability to comprehend explanations given to you by several posters now. Your attempt to demean Dawlish has backfired and made you look ignorant, stubborn, unwilling to leanr and stupid in roughly equal measure. Yes :-( I am only interested in the truth. Well then, read the Pictet experiment, but be prepared for a shock. Cheers, Alastair. |
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