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Old June 1st 06, 10:29 AM posted to uk.sci.weather
Weatherlawyer Weatherlawyer is offline
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Default calculating sunset


Bardo1ph wrote:
Hi. Can anyone help please? I need to know how to calculate the time
of sunset (using BST) on 2nd September, 2006 at Lat: 54:07:15 N,
Lon: 1.11.52 W.


You posted this to an astronomy group. What is the panic? I am sure
there will be an answer in plenty of time.

Consult an Ordinance Survey map to get an height for the location as
the variation of time with height is something in the region of 3
degrees for evry 50 feet IIRC. (If that equates to 15 degrees an hour,
it might be important.)

(And that is only for the observer. Check out the effects of the height
above sea level the observed horizon will be. Beware of dips and hills
too. Sunsets seem to follow them for some reason. They can be awkward
buggers Stars can. I think its all the sex and drugs.*)

Of course on a plain with no altitude as from a window or whatever the
equation is moot. If a rough estimate will do then it is about four
minutes past 6 that evening. I dare say the point at which the sun sets
is important too, so if there are houses and trees in the way you had
best get hold of a theodolite.

Have you posted to a surveyor's forum?

There is no BST on the Almanac I was using. I dare say you can work
that out for yourself. I would only get it wrong were I to do it for
you.

*Though I dare say you already knew that. If you didn't then a rock and
roll forum might help.