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Geostrophic winds cannot be exactly parallel to isobars
I keep seeing descriptions (e.g.
http://ww2010.atmos.uiuc.edu/(Gl)/guides/mtr/fw/fric.rxml) of winds blowing parallel to isobars. Yet surely this is not physically possible? The only force driving the wind is the pressure gradient force. The Coriolis force always acts perpendicular to the direction of movement, so it cannot do work--that is, change the kinetic energy of the wind in in any way. Look at it this way: the pressure gradient force is always perpendicular to the isobars. The Coriolis force is always perpendicular to the direction of the wind. So when the wind is moving parallel to the isobars, you have both forces acting perpendicular to its motion, leaving _no_ force acting in the direction of its motion. So what's keeping the wind moving against the drag of the ground? |
Geostrophic winds cannot be exactly parallel to isobars
On Fri, 20 Aug 2004 22:57:41 +1200,
Lawrence DčOliveiro , in wrote: + I keep seeing descriptions (e.g. + http://ww2010.atmos.uiuc.edu/(Gl)/guides/mtr/fw/fric.rxml) of winds + blowing parallel to isobars. Yet surely this is not physically possible? Geostrophic winds happen rarely in the real world. And they are, by definition, the component parallel to isobars. The ageostrophic component is perpendicular to the isobars. So, in reality, the winds look like this: wind = geostrophic + ageostrophic Now that's a bit of a simplification since those are vectors (direction and speed). James -- Consulting Minister for Consultants, DNRC I can please only one person per day. Today is not your day. Tomorrow isn't looking good, either. I am BOFH. Resistance is futile. Your network will be assimilated. |
Geostrophic winds cannot be exactly parallel to isobars
In article ,
(I R A Darth Aggie) wrote: On Fri, 20 Aug 2004 22:57:41 +1200, Lawrence DčOliveiro , in wrote: + I keep seeing descriptions (e.g. + http://ww2010.atmos.uiuc.edu/(Gl)/guides/mtr/fw/fric.rxml) of winds + blowing parallel to isobars. Yet surely this is not physically possible? Geostrophic winds happen rarely in the real world. And they are, by definition, the component parallel to isobars. I thought the definition http://ww2010.atmos.uiuc.edu/(Gl)/ww...hret=/guides/m tr/fw/fric.rxml was that the Coriolis force was in balance with the pressure gradient force. Which I took to mean, that component of the pressure gradient force perpendicular to the direction of the wind. As long as the drag is nonzero, there must be a component of the pressure gradient force in the direction of the motion of the wind, to offset the drag. So the wind can never be exactly parallel to the isobars. |
Geostrophic winds cannot be exactly parallel to isobars
"Lawrence DčOliveiro" wrote in message ... ... Which I took to mean, that component of the pressure gradient force perpendicular to the direction of the wind. As long as the drag is nonzero, there must be a component of the pressure gradient force in the direction of the motion of the wind, to offset the drag. So the wind can never be exactly parallel to the isobars. Why? The fact that the air is moving at all, is determined by the pressure gradient force (PGF). The fact that it's direction is 90 degrees offset to the PGF is a function of the coriolis effect... you cannot ask for *more* PGF in that direction. |
Geostrophic winds cannot be exactly parallel to isobars
"Lawrence DčOliveiro" wrote in message ... | I keep seeing descriptions (e.g. | http://ww2010.atmos.uiuc.edu/(Gl)/guides/mtr/fw/fric.rxml) of winds | blowing parallel to isobars. Yet surely this is not physically possible? | The only force driving the wind is the pressure gradient force. The | Coriolis force always acts perpendicular to the direction of movement, | so it cannot do work--that is, change the kinetic energy of the wind in | in any way. | | Look at it this way: the pressure gradient force is always perpendicular | to the isobars. The Coriolis force is always perpendicular to the | direction of the wind. So when the wind is moving parallel to the | isobars, you have both forces acting perpendicular to its motion, | leaving _no_ force acting in the direction of its motion. So what's | keeping the wind moving against the drag of the ground? The geostrophic wind is not a "real" wind. It is an "ideal" wind based on certain assumptions. One of these is that there is no friction against the ground, which is why it does not appear in the formulae used to calculate this wind. In the absence of ground friction, (which applies very nearly in the free atmosphere a kilometre or two up or more), the geostrophic wind is a very close approximation, providing the systems are not moving too quickly or are developing/decaying rapidly. These circumstances also produce effects not included in the geostrophic wind calculation. What happens with ground friction is that the wind speed is reduced from the geostrophic and so the coriolis force term drops. The pressure gradient force is then left unbalanced and the wind is deflected to blow at an angle towards low pressure, effectively filling it up. Just as well, really, for this limits the practical depth to which depressions can get and causes them to fill when the processes generating them are finished. Otherwise there is no telling how strong a hurricane could get (the same argument applies with cyclostrophic balance, which is when the pressure gradient force provides the acceleration required to maintain the moving air in a circular path - it balances the "centrigugal force" which also drops with windspeed). That ground friction drag prevents things being much worse than they actually are in the real world. -- - Yokel - oo oo OOO OOO OO 0 OO ) ( I ) ( ) ( /\ ) ( "Yokel" now posts via a spam-trap account. Replace my alias with stevejudd to reply. |
Geostrophic winds cannot be exactly parallel to isobars
In article ers.com,
"Icebound" wrote: "Lawrence DčOliveiro" wrote in message ... ... Which I took to mean, that component of the pressure gradient force perpendicular to the direction of the wind. As long as the drag is nonzero, there must be a component of the pressure gradient force in the direction of the motion of the wind, to offset the drag. So the wind can never be exactly parallel to the isobars. Why? The fact that the air is moving at all, is determined by the pressure gradient force (PGF). The fact that it's direction is 90 degrees offset to the PGF is a function of the coriolis effect... you cannot ask for *more* PGF in that direction. The work done by a force is the dot product of the force and the displacement of the object it's pushing on. In particular, if the two vectors (force and displacement) are at right angles, then the dot product is zero. Which means if the wind is moving at right angles to the pressure gradient force, then the pressure gradient force cannot transfer any kinetic energy to the wind, so it cannot cause the wind to blow. |
Geostrophic winds cannot be exactly parallel to isobars
In article ,
"Yokel" wrote: In the absence of ground friction, (which applies very nearly in the free atmosphere a kilometre or two up or more), the geostrophic wind is a very close approximation, providing the systems are not moving too quickly or are developing/decaying rapidly. These circumstances also produce effects not included in the geostrophic wind calculation. Another thing to keep in mind is that the Coriolis force increases with latitude. This means that, even in the complete absence of drag, the wind cannot follow a closed path (which is what an isobar is), as that would cause a pressure build-up at some point, which would stop the wind flowing. Thus, even neglecting drag, the idea of winds flowing parallel to isobars is still unrealistic. |
Geostrophic winds cannot be exactly parallel to isobars
Lawrence DčOliveiro wrote:
In article , "Yokel" wrote: In the absence of ground friction, (which applies very nearly in the free atmosphere a kilometre or two up or more), the geostrophic wind is a very close approximation, providing the systems are not moving too quickly or are developing/decaying rapidly. These circumstances also produce effects not included in the geostrophic wind calculation. Another thing to keep in mind is that the Coriolis force increases with latitude. This means that, even in the complete absence of drag, the wind cannot follow a closed path (which is what an isobar is), as that would cause a pressure build-up at some point, which would stop the wind flowing. Thus, even neglecting drag, the idea of winds flowing parallel to isobars is still unrealistic. I guess someone oughta tell the 500-mb flow that, then ;) Scott |
Geostrophic winds cannot be exactly parallel to isobars
In article ,
Scott wrote: Lawrence DčOliveiro wrote: In article , "Yokel" wrote: In the absence of ground friction, (which applies very nearly in the free atmosphere a kilometre or two up or more), the geostrophic wind is a very close approximation, providing the systems are not moving too quickly or are developing/decaying rapidly. These circumstances also produce effects not included in the geostrophic wind calculation. Another thing to keep in mind is that the Coriolis force increases with latitude. This means that, even in the complete absence of drag, the wind cannot follow a closed path (which is what an isobar is), as that would cause a pressure build-up at some point, which would stop the wind flowing. Thus, even neglecting drag, the idea of winds flowing parallel to isobars is still unrealistic. I guess someone oughta tell the 500-mb flow that, then ;) You have some empirical evidence contradicting my claim? |
Geostrophic winds cannot be exactly parallel to isobars
Lawrence DčOliveiro wrote:
In article , Scott wrote: Lawrence DčOliveiro wrote: In article , "Yokel" wrote: In the absence of ground friction, (which applies very nearly in the free atmosphere a kilometre or two up or more), the geostrophic wind is a very close approximation, providing the systems are not moving too quickly or are developing/decaying rapidly. These circumstances also produce effects not included in the geostrophic wind calculation. Another thing to keep in mind is that the Coriolis force increases with latitude. This means that, even in the complete absence of drag, the wind cannot follow a closed path (which is what an isobar is), as that would cause a pressure build-up at some point, which would stop the wind flowing. Thus, even neglecting drag, the idea of winds flowing parallel to isobars is still unrealistic. I guess someone oughta tell the 500-mb flow that, then ;) You have some empirical evidence contradicting my claim? If you're talking *exactly* parallel to the isobars at all times, no. But the 500 mb winds do flow generally approximately parallel to the isobars, to within a good enough approximation for many purposes, especially in areas of respectable gradients. A look at a couple of 500 mb synoptic charts will show that. For instance see http://www.hpc.ncep.noaa.gov/dailywx..._20040101.html . Note that the contours are isoheights of the 500 mb surface, not isobars, but it makes no difference to Scott's point. If you want to dig out a meteorology text from the 1940s or 1950s, when they still used isobars on a constant height surface, be my guest. Cheers, Russell -- All too often the study of data requires care. |
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