Home |
Search |
Today's Posts |
![]() |
|
uk.sci.weather (UK Weather) (uk.sci.weather) For the discussion of daily weather events, chiefly affecting the UK and adjacent parts of Europe, both past and predicted. The discussion is open to all, but contributions on a practical scientific level are encouraged. |
Reply |
|
LinkBack | Thread Tools | Display Modes |
#1
![]() |
|||
|
|||
![]()
Hello everyone,
I have what is probably a rather simple question here - but I'm struggling to solve it myself. I have a number of measurements of Integrated Water Vapour, in units of kg/m^2 and I need to provide this as an input to a model as Precipitable Water Content in cm. Is there an easy way to convert between these? As far as I am aware, the definition of PWC is the height of the water if all of the water in the air column was precipitated out, so I guess this question is basically "What is the height in cm of X kg/m^2 of water?" - is that possible to answer with a simple conversion formulae? Any help would be much appreciated, Best regards, Robin |
#2
![]() |
|||
|
|||
![]() wrote in message news:25950344.2484.1336483371719.JavaMail.geo-discussion-forums@ynja13... Hello everyone, I have what is probably a rather simple question here - but I'm struggling to solve it myself. I have a number of measurements of Integrated Water Vapour, in units of kg/m^2 and I need to provide this as an input to a model as Precipitable Water Content in cm. Is there an easy way to convert between these? As far as I am aware, the definition of PWC is the height of the water if all of the water in the air column was precipitated out, so I guess this question is basically "What is the height in cm of X kg/m^2 of water?" - is that possible to answer with a simple conversion formulae? Any help would be much appreciated, Best regards, Robin ================ 1 kg/m^2 of water will have a height of 0.1cm. Total column precipitable water in the UK at sea level will normally range from 10 to 40mm, occasionally higher or lower. Will -- |
#3
![]() |
|||
|
|||
![]() |
#4
![]() |
|||
|
|||
![]()
wrote in message
news:25950344.2484.1336483371719.JavaMail.geo-discussion-forums@ynja13... Hello everyone, I have what is probably a rather simple question here - but I'm struggling to solve it myself. I have a number of measurements of Integrated Water Vapour, in units of kg/m^2 and I need to provide this as an input to a model as Precipitable Water Content in cm. Is there an easy way to convert between these? As far as I am aware, the definition of PWC is the height of the water if all of the water in the air column was precipitated out, so I guess this question is basically "What is the height in cm of X kg/m^2 of water?" - is that possible to answer with a simple conversion formulae? Any help would be much appreciated, Best regards, Robin mw = r * (p1-p2) / g, where mw is the precipitatable water, r is the mean value of water vapour (over the layer confined by pressures p1 and p2), and g is acc due to gravity. If r is in grammes per kg, and g in m per sec per sec, then mw will be in units of 0.1 mm. -- Bernard Burton Wokingham Berkshire. Weather data and satellite images at: http://www.woksat.info/wwp.html |
#5
![]() |
|||
|
|||
![]() "Bernard Burton" wrote in message ... wrote in message news:25950344.2484.1336483371719.JavaMail.geo-discussion-forums@ynja13... Hello everyone, I have what is probably a rather simple question here - but I'm struggling to solve it myself. I have a number of measurements of Integrated Water Vapour, in units of kg/m^2 and I need to provide this as an input to a model as Precipitable Water Content in cm. Is there an easy way to convert between these? As far as I am aware, the definition of PWC is the height of the water if all of the water in the air column was precipitated out, so I guess this question is basically "What is the height in cm of X kg/m^2 of water?" - is that possible to answer with a simple conversion formulae? Any help would be much appreciated, Best regards, Robin mw = r * (p1-p2) / g, where mw is the precipitatable water, r is the mean value of water vapour (over the layer confined by pressures p1 and p2), and g is acc due to gravity. If r is in grammes per kg, and g in m per sec per sec, then mw will be in units of 0.1 mm. Bernard, are you sure? Whole mm surely? Will -- |
#6
![]() |
|||
|
|||
![]()
Yes Will, that is the fact.
Example, for a saturated column at Theta-w 10C, and taking the mean r per 100 mbar from 1000 up to 400 mbar, the values of r are 7, 5.7, 4, 2.6, 1.4 and 0.6 g/kg. That gives a total r of 21.3 * 100/9.8, or appx 213 units of 0.1 mm, or 21.3 mm. (7 * 100) + (5.7 * 100)....etc / 9.8 -- Bernard Burton Wokingham Berkshire. Weather data and satellite images at: http://www.woksat.info/wwp.html "Dartmoor Will" wrote in message ... "Bernard Burton" wrote in message ... wrote in message news:25950344.2484.1336483371719.JavaMail.geo-discussion-forums@ynja13... Hello everyone, I have what is probably a rather simple question here - but I'm struggling to solve it myself. I have a number of measurements of Integrated Water Vapour, in units of kg/m^2 and I need to provide this as an input to a model as Precipitable Water Content in cm. Is there an easy way to convert between these? As far as I am aware, the definition of PWC is the height of the water if all of the water in the air column was precipitated out, so I guess this question is basically "What is the height in cm of X kg/m^2 of water?" - is that possible to answer with a simple conversion formulae? Any help would be much appreciated, Best regards, Robin mw = r * (p1-p2) / g, where mw is the precipitatable water, r is the mean value of water vapour (over the layer confined by pressures p1 and p2), and g is acc due to gravity. If r is in grammes per kg, and g in m per sec per sec, then mw will be in units of 0.1 mm. Bernard, are you sure? Whole mm surely? Will -- Yes Will, I am sure. Example, for a saturated column at Theta-w 10C, and taking the mean r per 100 mbar from 1000 up to 400 mbar, the values of r are 7, 5.7, 4, 2.6, 1.4 and 0.6 g/kg. That gives a total r of 21.3 * 100/9.8, or appx 213 units of 0.1 mm, or 21.3 mm. (7 * 100) + (5.7 * 100)....etc / 9.8 -- Bernard Burton Wokingham Berkshire. Weather data and satellite images at: http://www.woksat.info/wwp.html |
#7
![]() |
|||
|
|||
![]() "Bernard Burton" wrote in message ... Yes Will, that is the fact. Example, for a saturated column at Theta-w 10C, and taking the mean r per 100 mbar from 1000 up to 400 mbar, the values of r are 7, 5.7, 4, 2.6, 1.4 and 0.6 g/kg. That gives a total r of 21.3 * 100/9.8, or appx 213 units of 0.1 mm, or 21.3 mm. (7 * 100) + (5.7 * 100)....etc / 9.8 -- Bernard Burton Wokingham Berkshire. Weather data and satellite images at: http://www.woksat.info/wwp.html "Dartmoor Will" wrote in message ... "Bernard Burton" wrote in message ... wrote in message news:25950344.2484.1336483371719.JavaMail.geo-discussion-forums@ynja13... Hello everyone, I have what is probably a rather simple question here - but I'm struggling to solve it myself. I have a number of measurements of Integrated Water Vapour, in units of kg/m^2 and I need to provide this as an input to a model as Precipitable Water Content in cm. Is there an easy way to convert between these? As far as I am aware, the definition of PWC is the height of the water if all of the water in the air column was precipitated out, so I guess this question is basically "What is the height in cm of X kg/m^2 of water?" - is that possible to answer with a simple conversion formulae? Any help would be much appreciated, Best regards, Robin mw = r * (p1-p2) / g, where mw is the precipitatable water, r is the mean value of water vapour (over the layer confined by pressures p1 and p2), and g is acc due to gravity. If r is in grammes per kg, and g in m per sec per sec, then mw will be in units of 0.1 mm. Bernard, are you sure? Whole mm surely? Will -- Yes Will, I am sure. Example, for a saturated column at Theta-w 10C, and taking the mean r per 100 mbar from 1000 up to 400 mbar, the values of r are 7, 5.7, 4, 2.6, 1.4 and 0.6 g/kg. That gives a total r of 21.3 * 100/9.8, or appx 213 units of 0.1 mm, or 21.3 mm. (7 * 100) + (5.7 * 100)....etc / 9.8 Ah yes, my mistake. Thanks Bernard. Will -- |
#8
![]() |
|||
|
|||
![]()
On May 8, 2:43*pm, "Dartmoor Will" wrote:
wrote in message news:25950344.2484.1336483371719.JavaMail.geo-discussion-forums@ynja13... Hello everyone, I have what is probably a rather simple question here - but I'm struggling to solve it myself. I have a number of measurements of Integrated Water Vapour, in units of kg/m^2 and I need to provide this as an input to a model as Precipitable Water Content in cm. Is there an easy way to convert between these? As far as I am aware, the definition of PWC is the height of the water if all of the water in the air column was precipitated out, so I guess this question is basically "What is the height in cm of X kg/m^2 of water?" - is that possible to answer with a simple conversion formulae? Any help would be much appreciated, Best regards, Robin ================ 1 kg/m^2 of water will have a height of 0.1cm. Total column precipitable water in the UK at sea level will normally range from 10 to 40mm, occasionally higher or lower. Will -- Just in case you're interested, on Mars the global average is around 10 microns of precipitable water, though in the summer when the north polar cap sublimates it can get up to a whopping 80 microns. :-) Liam |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Difference between Integrated Water Vapour and Precipitable Water Content | uk.sci.weather (UK Weather) | |||
Precipitable water vapor and the amount of rainfall. | sci.geo.meteorology (Meteorology) | |||
How to estimate precipitable water from surface data? | sci.geo.meteorology (Meteorology) | |||
Water vapour: feedback or forcing? | sci.geo.meteorology (Meteorology) | |||
Water vapour "plume" across Pacific? | sci.geo.meteorology (Meteorology) |