Stephen Burt wrote:
On 25 Sep, 21:10, Scott W wrote:

Evenin' all, could somebody tell me how glass rainfall measures are
calibrated ... ie how many mm of rain from a Snowdon pattern gauge
does it take to make up 1ml of water in a glass measure?

The reason being ordinary glass measures that measure as little as 1mm
are far cheaper to buy than designated rainfall measure-glasses.

Hope that makes sense...


Volume of a cylinder = pi r squared x h

Where r = radius and h - height

For a standard 'five inch' raingaguge funnel, diamter = 127 mm, then r
= 63.5 mm: and for 1 mm of rainfall (= h), then pi r2 h = 63.5 x 63.5
x 1 = 4032 mm3 = 4.0 cm3 (ml)

.... and "pi == 1" ;-)

The result should be 1 mm per each 12.668 ml accumulated in that rain gauge.

On 26 Sep, 22:05, ldpc wrote:
Stephen Burt wrote:
On 25 Sep, 21:10, Scott W wrote:

Evenin' all, could somebody tell me how glass rainfall measures are
calibrated ... ie how many mm of rain from a Snowdon pattern gauge
does it take to make up 1ml of water in a glass measure?

The reason being ordinary glass measures that measure as little as 1mm
are far cheaper to buy than designated rainfall measure-glasses.

Hope that makes sense...

Volume of a cylinder = pi r squared x h

Where r = radius and h - height

For a standard 'five inch' raingaguge funnel, diamter = 127 mm, then r
= 63.5 mm: and for 1 mm of rainfall (= h), then pi r2 h = 63.5 x 63.5
x 1 = 4032 mm3 = 4.0 cm3 (ml)

... and "pi == 1" ;-)

The result should be 1 mm per each 12.668 ml accumulated in that rain gauge.- Hide quoted text -

- Show quoted text -

Pi is, of course, 1.00 only late in the evening after a glass of wine
and when replying to usw questions. At all other times it resumes its
normal value. You are perfectly correct, thanks for spotting my
omission!

--
Stephen Burt
Stratfield Mortimer, Berkshire