The passage of yesterday's classic strong ana-cold front, recorded on the
Wokingham AWS, can be seen at:

http://www.woksat.info/cs/ejsgr101105.gif

--
Bernard Burton

Wokingham Berkshire.

Weather data and satellite images at:
www.woksat.info/wwp.html

On Nov 6, 10:10*am, "Bernard Burton"
wrote:
The passage of yesterday's classic strong ana-cold front, recorded on the
Wokingham AWS, can be seen at:

http://www.woksat.info/cs/ejsgr101105.gif

--
Bernard Burton

Wokingham Berkshire.

Weather data and satellite images at:www.woksat.info/wwp.html

A similar record here according to my rickety old thermograph -
slightly less intense and one hour later. Impressive instrumentation!

Tudor Hughes, Warlingham, NE Surrey 556 ft.

On Sat, 6 Nov 2010 at 10:10:10, Bernard Burton
wrote in uk.sci.weather :

The passage of yesterday's classic strong ana-cold front, recorded on the
Wokingham AWS, can be seen at:

http://www.woksat.info/cs/ejsgr101105.gif

BTW, what is the 'humidity mixing ratio'?
--
Paul Hyett, Cheltenham (change 'invalid83261' to 'blueyonder' to email me)

"Paul Hyett" wrote in message
...
On Sat, 6 Nov 2010 at 10:10:10, Bernard Burton
wrote in uk.sci.weather :

The passage of yesterday's classic strong ana-cold front, recorded on the
Wokingham AWS, can be seen at:

http://www.woksat.info/cs/ejsgr101105.gif

BTW, what is the 'humidity mixing ratio'?

The amount of water vapour (kg) per kilogram of dry air.
If q is the amount of water vapour then HMR = q/(m-q) where m is the mass of
air (including water vapour).

Another measure is specific humidity (SH) which is q/m.

If we let q = m *SH then
HMR= m*SH/(m-m*SH) or
HMR = SH/(1-SH)

Will
--

On Nov 6, 10:10*am, "Bernard Burton"
wrote:
The passage of yesterday's classic strong ana-cold front, recorded on the
Wokingham AWS, can be seen at:

http://www.woksat.info/cs/ejsgr101105.gif


Bernard,

Nice temperature trace of the Ana Cold Front passing though - the
front went through my location around 23:00hrs Temperature fell 3.6'C
between 22:50 - 24:00hrs. Interestingly, my 1 minute RH only shows a
small rise between these times with a slight stepped 'kick' at
23:30hrs

Best Wishes

Richard Griffith
Horsham AWS

On Sat, 6 Nov 2010 at 17:53:06, Will Hand
wrote in uk.sci.weather :

BTW, what is the 'humidity mixing ratio'?

The amount of water vapour (kg) per kilogram of dry air.
If q is the amount of water vapour then HMR = q/(m-q) where m is the
mass of air (including water vapour).

Another measure is specific humidity (SH) which is q/m.

If we let q = m *SH then
HMR= m*SH/(m-m*SH) or
HMR = SH/(1-SH)

Thanks.
--
Paul Hyett, Cheltenham (change 'invalid83261' to 'blueyonder' to email me)