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uk.sci.weather (UK Weather) (uk.sci.weather) For the discussion of daily weather events, chiefly affecting the UK and adjacent parts of Europe, both past and predicted. The discussion is open to all, but contributions on a practical scientific level are encouraged. |
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#1
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Given wind velocity, barometric pressure, humidity and any other relevant
parameter how can the pressure (say psi) perpendicular to wind direction be calculated? I live in hurricane Ivan's path and I would like to know the energy being experienced by the side of a building. Some parameters I know about are Wind Speed was 130 mph, barometric pressure was 920 millibars. Peter. |
#2
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I live in hurricane Ivan's path and I would like to know the
energy being experienced by the side of a building. Some parameters I know about are Wind Speed was 130 mph, barometric pressure was 920 millibars. About 45 lb per square foot. This is only a back-of-an-envelope calculation based on a formula for the head-on air resistance of non-streamlined railway trains. Tudor Hughes, Warlingham, Surrey. |
#3
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On 17 Sep 2004 14:59:40 GMT, (TudorHgh) wrote:
I live in hurricane Ivan's path and I would like to know the energy being experienced by the side of a building. Some parameters I know about are Wind Speed was 130 mph, barometric pressure was 920 millibars. About 45 lb per square foot. This is only a back-of-an-envelope calculation based on a formula for the head-on air resistance of non-streamlined railway trains. Pretty much spot-on according to this nice page I found the other day: http://www.madsci.org/posts/archives...8418.Eg.r.html There's a nice simple table among all the formulae - about two screens down from the top. -- Dave |
#4
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![]() "Dave Ludlow" schreef in bericht ... On 17 Sep 2004 14:59:40 GMT, (TudorHgh) wrote: I live in hurricane Ivan's path and I would like to know the energy being experienced by the side of a building. Some parameters I know about are Wind Speed was 130 mph, barometric pressure was 920 millibars. About 45 lb per square foot. This is only a back-of-an-envelope calculation based on a formula for the head-on air resistance of non-streamlined railway trains. Pretty much spot-on according to this nice page I found the other day: http://www.madsci.org/posts/archives...8418.Eg.r.html There's a nice simple table among all the formulae - about two screens down from the top. -- Dave A rough indication of the wind pressure on a flat plate with a surface of one square meter is 1/16 * V * V kilograms, where V is the windspeed in meters per second. The factor depends on the pressure and temperature of the air. Sytze Stel |
#5
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Many thanks guys. 45 pounds per square foot is huge. It is no wonder that
even brick and concrete walls were destroyed. There was one case where a commercial air conditioning unit (about 3'x4'x4', these things are heavy) was blown off the roof onto a car below. The car was trashed. We experienced much rain (4") but not much wind. Peter. "PVR" wrote in message ... Given wind velocity, barometric pressure, humidity and any other relevant parameter how can the pressure (say psi) perpendicular to wind direction be calculated? I live in hurricane Ivan's path and I would like to know the energy being experienced by the side of a building. Some parameters I know about are Wind Speed was 130 mph, barometric pressure was 920 millibars. Peter. |
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